Question

Let $f:R\to R$ be defined by $f\left(x\right)=x^3+5$ then find $f^{-1}\left(x\right)$

Answer 1

let $f\left(x\right)=x^3+5=y$

$y-5=x^3$

$x=(y-5{)}^{\frac{1}{3}}$

so therefore $f^{-1}\left(x\right)=(x-5{)}^{\frac{1}{3}}$