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Question

Let f(x)=x1+x2. Then range of f is


Correct Answer
A
[12,12]
Your Answer
B
[12,12]{0}
Your Answer
C
(12,12)
Your Answer
D
(12,12){0}

Solution

The correct option is A [12,12]
f(x)=x1+x2
Denominator is 1+x2.
1+x20 for any real value of x.
Hence, domain of f is R.

Now, let y=f(x)
y=x1+x2yx2x+y=0x=1±14y22y
For x to be defined,
14y20, y0
y[12,12]{0}
But for x=0,y=0
R(f)=[12,12]

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