Question

Let f(x)=⎧⎨⎩x3+x2−16x+20(x−2)2,if x≠2 k, if x=2 f f(x)be continuous for all x, then k =7-7±7None of these

Solution

The correct option is A 7For continuous limx→2f(x)=f(2)=k ⇒k=limx→2x3+x2−16x+20(x−2)2 =limx→2(x2−4x+4)(x+5)(x−2)2=7

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