CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Let f(x)={tan1x:|x|1x214:|x|<1. Then domain of f'(x) is:


A
R{1}
loader
B
R{1,0,1}
loader
C
R{1,1}
loader
D
{1}
loader

Solution

The correct option is C R{1,1}
f(x)={tan1x:|x|1x214:|x|<1=⎪ ⎪⎪ ⎪tan1x:x1x214:1<x<1tan1x:x1

Clearly f(x) is discontinuous at change points –1 and 1 and therefore not differentiable at x = –1, 1.
 Domain f(x)=R{1.1}
 

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image