CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let g(x)=1+x[x] and f(x)=1x<00x=01x>0. Then for all x,f[g(x)] is equal to

A
x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
f(x)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
g(x)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1
We have,
g(x)={1+nn=1,x=nZ1+n+kn=1+k,x=n+k
where nZ,0<k<1
Now f[g(x)]=1g(x)<00g(x)=01g(x)>1
Clearly, g(x)>0 for all x. So f[g(x)]=1, for all x.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vector Addition
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon