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Question

Let $$g(x)$$ be the function defined [-1,1]. If the area of the equilateral triangle with two of its vertices at (0, 0) and $$(x, g(x))$$ is $$\sqrt3 / 4$$ then the function of $$g(x)$$ is                                                                                                                                 (IIT-JEE, 1989)


A
g(x)=±1x2
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B
g(x)=1x2
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C
g(x)=1x2
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D
g(x)=1+x2
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Solution

The correct options are
B $$g(x) = \sqrt{1 - x^2}$$
C $$g(x) = - \sqrt{1 - x^2}$$
1770582_1754824_ans_2a20899a2924423d99c2c2b7ecf84f85.jpeg

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