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Quantitative Aptitude

Functions

Let gx=|x+1| ...

Question

Let g(x)= |x+1|. The number of values that 'x' can take (given that its range is between -2 $&$ + 2 (both inclusive) for which g(x-3), g(x-1), g(x+1) are in AP is?

A

1

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B

2

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C

0

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D

4

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Solution

The correct option is B
2

g(x-3) = |x-2|

g(x-1)=|x|

g(x+1)= |x+2|

These will be in AP if

2|x| = |x-2|+|x+2|

Only x= -2 and x=2 satisfy the above equation in the given range.

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