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Question

Let (α,β,γ) and Q(1,1,0) be two points such that the mid-point of PQ is R(x,y,z). If x is the A.M. of α and β, y is the G.M. of β and γ rand z is the H.M. of γ and α, then

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Solution

Since R is the midpoint of PQ, we have
2x=α+1,2y=β1,2z=γ
Also, 2x=α+β since x is the A.M. of α & β.
y2=β×γ
z=2α×γα+γ
Using the above relations, β=1.
Also, 4α=α+γ, or γ=3α
Also, since β is 1,y=0.
Hence, γ becomes 0, implying α to be 0.
So, α+β+γ=1

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