Question

Let m be the mid-point and u be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is __________.

Answer 1

Mid-value of the class = m

Upper limit of the class = u

We know

Mid-value of the class = $\frac{1}{2}$(Lower limit of the class + Upper limit of the class)

∴ m = $\frac{1}{2}$(Lower limit of the class + u) (Given)

⇒ Lower limit of the class + u = 2m

⇒ Lower limit of the class = 2m − u

Thus, the lower limit of the class is 2m − u.

Let m be the mid-point and u be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is ___2m − u____.