Let n U -700- n A -200- n B -300 and n A - B -100- then n A C - B c equals toA- 400- 600- 300D- 20

The correct option is C 300n(U)=700, n(A)=200, n(B)=300 n(A∩ B)=100 n(A^c∩ B^c) =n(A∪ B)^c =n(U) n(A∪ B) =700 n(A) n(B)+n(A∩ B) =700 200 300+100=300 ...

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Byju's Answer

Standard XII

Mathematics

Properties of Set Operation

Let n U =700,...

Question

Let $n (U) = 700, n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100$ , then $n (A^{c} \cap B^{c})$ equals to

400

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600

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300

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20

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Solution

The correct option is C $300$
$n (U) = 700, n (A) = 200, n (B) = 300 n (A \cap B) = 100 n (A^{c} \cap B^{c}) = n (A \cup B)^{c} = n (U) - n (A \cup B) = 700 - n (A) - n (B) + n (A \cap B) = 700 - 200 - 300 + 100 = 300$

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Let n(U)=700,n(A)=200,n(B)=300 and n(A∩B)=100, then n(Ac∩Bc) equals to

The correct option is C 300n(U)=700,n(A)=200,n(B)=300n(A∩B)=100n(Ac∩Bc)=n(A∪B)c=n(U)−n(A∪B)=700−n(A)−n(B)+n(A∩B)=700−200−300+100=300

Let $n (U) = 700, n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100$ , then $n (A^{c} \cap B^{c})$ equals to

The correct option is C $300$
$n (U) = 700, n (A) = 200, n (B) = 300 n (A \cap B) = 100 n (A^{c} \cap B^{c}) = n (A \cup B)^{c} = n (U) - n (A \cup B) = 700 - n (A) - n (B) + n (A \cap B) = 700 - 200 - 300 + 100 = 300$