Question

# Let O(0,0),P(3,4),Q(6,0) be the vertices of the triangle OPQ. The point R inside the tringle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R are  (43,3)(3,23)(3,43)(43,23)

Solution

## The correct option is C (3,43)∵Ar(ΔOPR)=Ar(ΔPQR)=Ar(ΔOQR) ∴ by simply geometry  Rshould be the centroid of ΔPQO ⇒R(3+6+03,4+0+03)=(3,43)

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