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Question

Let O(0,0),P(3,4),Q(6,0) be the vertices of the triangle OPQ. The point R inside the tringle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R are
 
  1. (43,3)
  2. (3,23)
  3. (3,43)
  4. (43,23)
     


Solution

The correct option is C (3,43)
Ar(ΔOPR)=Ar(ΔPQR)=Ar(ΔOQR)


by simply geometry 
Rshould be the centroid of ΔPQO
R(3+6+03,4+0+03)=(3,43)

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