Triangle PQR has S as itsA- centroidB- orthocenterC- incentreD- circumcentre

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Dot Product of Two Vectors

triangle PQR ...

Question

Let O be the origin and let PQR be an arbitrary triangle. The point S is such that OP.OQ + OR.OS = OR.OP + OQ.OS = OQ.OR + OP.OS Then the triangle PQR has S as its

centroid

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orthocenter

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incentre

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circumcentre

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Solution

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Similar questions

O

P Q R

S

- - \to O P \cdot - - \to O Q + - - \to O R \cdot - - \to O S = - - \to O R \cdot - - \to O P + - - \to O Q \cdot - - \to O S = - - \to O Q . - - \to O R + - - \to O P . - - \to O S

P Q R

S

18, 24

30

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