CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Let origin is one vertex of an equilateral triangle of side length a units. If other vertex lies on the line x3y=0 in the first quadrant, then the co-ordinates of third vertex is/are


A
(0,a)
loader
B
(0,a)
loader
C
(3a2,a2)
loader
D
(3a2,a2)
loader

Solution

The correct options are
B (0,a)
C (3a2,a2)
Given line: x=3y
Slope m=13
So it makes an angle of 30 with xaxis in anticlockwise direction.
Now the two possible choices for third vertex make an angle of 90 and 30 with x axis.
Now, using parametric coordinates, we get
(0+acosθ,0+asinθ)

Therefore, the possible coordinates third vertex are
(acos90,asin90)=(0,a)(acos(30),asin(30))=(3a2,a2)

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image