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Question

Let c be a vector perpendicular to the vectors a=^i+^j^k and b=^i+2^j+^k. If c(^i+^j+3^k), then the value of c(a×b) is equal to

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Solution

c(a×b)=[c a b]
a×b=∣ ∣ ∣^i^j^k111121∣ ∣ ∣=(3,2,1)

Given, ca and cb
c || a×b
c=λ(a×b)
c=λ(3i2j+k)

c(^i+^j+3^k)=8
3λ2λ+3λ=8
4λ=8λ=2
c=6^i4^j+2^k
c(a×b)=[c a b]
=∣ ∣642111121∣ ∣=18+8+2=28

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