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Question

Let PQ and RS be tangents at the extremities of the diameter PR of a circle of radius r. If PS and RQ intersect at a point X on the circumference of the circle, then 2r equals


A
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B
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C
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D
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Solution

The correct option is A
α+β=π2
tanαtanβ=1
RSPR×PQPR=1
(PR)2=RS.PQ
PR=RS.PQ
2r=RS.PQ

Mathematics

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