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Question

Let pqr be a three digit number. Then, pqr + qrp + rpq is not divisible by



A

9

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B

37

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C

3

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D

p + q + r

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Solution

The correct option is A

9


pqr = 100p + 10q + r

qrp = 100 q + 10r + p

rpq = 100r + 10p + q

Adding all three,
pqr + qrp + rpq = 100(p + q +r) + 10(p + q + r) + (p + q + r) = 111 (p + q +r) = 37 × 3 (p + q + r)

(pqr + qrp + rpq) is divisible by 37, 3 and (p + q + r)


Mathematics

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