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Question

Let R be a relation on the set N be defined by {(x,y)|x,y|N,2x+y=41}. Then R is


A

Reflexive

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B

Symmetric

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C

Transitive

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D

None of these

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Solution

The correct option is D

None of these


On the set N of natural numbers,

R = {(x,y): x,y N , 2x + y = 41}.

Since (1,1) R as 2.1+1 = 3 41. So R is not reflexive.

(1,39) R But (39,1) R . So R is not symmetric, (20,1)

(1,39) R . But (20,39) R. So R is not transitive .


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