Question

Let $\ast :R\times R\to R$ given by $(a,b)\to a+4b^2$ is a binary operation, compute $(-5)\ast (2\ast 0)$.

Answer 1

We have, $\ast :R\times R\to R$, given by

$(a,b)=a+4b^2$

Therefore,

$(-5)\ast (2\ast 0)=(-5)[2+4(0{)}^2]=(-5)\ast (2)$

$=-5+4(2{)}^2=-5+16=11$