Let S k - 1 - 2 - 3 - - - k k - If S 1 2 - S 2 2 - S 10 2 - 5 12 A then A is equal to -

The correct option is A 303 S _ K = K + 1 2 Σ S _ k ^ 2 = 5 12 A ∑ _ k = 1 ^ 10 ( K + 1 2 ) ^ 2 = 2 ^ 2 + 3 ^ 2 ...

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Summation by Sigma Method

Let S k = ...

Question

Let $S_{k} = \frac{1 + 2 + 3 + \dots + k}{k} .$ If $S_{1}^{2} + S_{2}^{2} + + S_{10}^{2} = \frac{5}{12} A$ then $A$ is equal to :

303

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283

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301

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Similar questions

S_{k} = \frac{1 + 2 + 3 + . . . . + k}{k} .

S_{1}^{2} + S_{2}^{2} + . . . + S_{10}^{2} = \frac{5}{12} A

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S_{k} = \frac{1 + 2 + 3 + . . . . + k}{k} .

S_{1}^{2} + S_{2}^{2} + . . . + S_{10}^{2} = \frac{5}{12} A

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Let $S (K) = 1 + 3 + 5 + . . . . . + (2 K - 1) = 3 + K^{2}$ . Then which of the following is true?

If $S_{1}, S_{2}, S_{3}$ be respectively the sums of n, 2n, 3n terms of a G.p., then prove $S_{1}^{2} + S_{2}^{2} = S_{1} (S_{2} + S_{3})$ .

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