Let A -2 -3 -k- and B - then component of A perpendicular to B isA- 0-5 -0-5 -k-B- 2-5 -2-5 -k-C- -1-5 -1-5 -k-D- 1-5 -2-5 -k-

The correct option is B 2.5î+2.5 ĵ k̂ Let A⃗_⃗1⃗ and A⃗_⃗2⃗ be vectors along B⃗ and ⊥ to B⃗ |A⃗|cos θ B̂=A⃗_⃗1⃗ A⃗_⃗1⃗=A⃗.B⃗/BB̂=(2 3)/√(2).î ĵ/√(2)= î+ĵ/2 ...

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Byju's Answer

Standard XII

Mathematics

Theorems for Differentiability

Let A =2 î+3 ...

Question

Let $\to A = 2^i + 3^j -^k$ and $\to B =^i -^j$ , then component of $\to A$ perpendicular to $\to B$ is

0.5^i - 0.5^j -^k

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2.5^i + 2.5^j -^k

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- 1.5^i - 1.5^j +^k

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1.5^i + 2.5^j -^k

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Solution

The correct option is B $2.5^i + 2.5^j -^k$

Let $_{1}$ and $_{2}$ be vectors along $\to B$ and $⊥$ to $\to B$

$| \to A | c o s θ^B =_{1}$

$_{1} = \frac{\to A . \to B}{B}^B = \frac{(2 - 3)}{\sqrt{2}} . \frac{^i -^j}{\sqrt{2}} = \frac{-^i +^j}{2}$

$\to A =_{1} +_{2} \Rightarrow_{2} = \to A -_{1} = 2^i + 3^j -^k + \frac{^i}{2} - \frac{^j}{2}$

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Similar questions

If $\to r \times \to b = \to c \times \to b$ and $\to r . \to a = 0$ where $\to a = 2^i + 3^j -^k, \to b = 3^i -^j +^k$ and $\to c =^i +^j + 3^k$ , then $\to r$ is equal to