CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let a=2^i+^j2^k and b=^i+^j. If c is a vector such that a.c=|c|, |ca|=22 and the angle between (a×b) and c is 30 ,then |(a×b)×c| is equal to

A
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 32
In this question, vector c is not given, therefore, we cannot apply the formulae of (a×b×c) (vector triple product).
Now, |(a×b)×c|=|a×b||c|sin 30 ...(i)Again,|a×b|=∣ ∣ ∣^i^j^k212110∣ ∣ ∣=2^i2^j+^k|a×b|=22+(2)2+1=4+4+1=9=3Since,|ca|=22 [given]|ca|2=8(ca).(ca)=8c.cc.aa.c+a.a=8|c|2+|a|22|c|=8|c|2+92|c|=8|c|22|c|+1=0(|c|1)2=0|c|=1From,Eq.(i),|(a×b)×c|=(3)(1).(12)=32


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vector Product
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon