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Question

Let a=ˆi+ˆj and b=2ˆiˆk, then the point of intersection of lines r×a=b×a and r×b=a×b is

A
ˆi+ˆj+ˆk
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B
3ˆiˆj+ˆk
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C
3ˆi+ˆjˆk
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D
ˆiˆjˆk
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Solution

The correct option is C 3ˆi+ˆjˆk
r×a=b×ar=b+λa
and r×b=a×br=a+μb
For intersection of both the lines, b+λa=a+μb
Comparing coefficients, λ=μ=1
Hence point of intersection is r=a+b=3^i+^j^k

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