Let →a=ˆi+ˆj and →b=2ˆi−ˆk, then the point of intersection of lines →r×→a=→b×→a and →r×→b=→a×→b is
A
ˆi+ˆj+ˆk
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B
3ˆi−ˆj+ˆk
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C
3ˆi+ˆj−ˆk
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D
ˆi−ˆj−ˆk
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Solution
The correct option is C3ˆi+ˆj−ˆk →r×→a=→b×→a⇒→r=→b+λ→a and →r×→b=→a×→b⇒→r=→a+μ→b For intersection of both the lines, →b+λ→a=→a+μ→b Comparing coefficients, λ=μ=1 Hence point of intersection is →r=→a+→b=3^i+^j−^k