Let u- v-w-2-3k- If n- is a unit vector such that u-n-0- v-n-0- then -w-n-

$\to V = 2^i +^j -^k$ and $\to W =^i + 3^k$ . If $\to U$ is a unit vector, then the maximum value of the scalar triple product $[\to U \to V \to W]$ is

Q. If

\to u =^j + 4^k

\to v =^i - 3^k

, and

\to w = cos θ^i + sin θ^j

are vectors in

3

-dimensional space, then the maximum possible value of

| \to u \times \to v \cdot \to w |

is?

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Let →u=^i+^j, →v=^i−^j,→w=^i+2^j+3^k. If →n is a unit vector such that →u⋅→n=0, →v⋅→n=0, then |→w⋅→n|=

The correct option is B 3→U.→n=o & →V.→n=owhich mean →n is ⊥ to →U & →v→n=→U×→V|→U×→V|→U×→V=∣∣ ∣ ∣∣^i^j^k1101−10∣∣ ∣ ∣∣=−2^k^n=−^k|→w.→n|=3

Let $\to u =^i +^j, \to v =^i -^j, \to w =^i + 2^j + 3^k$ . If $\to n$ is a unit vector such that $\to u \cdot \to n = 0, \to v \cdot \to n = 0$ , then $| \to w \cdot \to n | =$