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Question

Let z=x+iy and ω=1izzi. If |ω|=1, then z lies on

A
the imaginary axis
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B
on the real axis
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C
a unit circle
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D
a parabola
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Solution

The correct option is B on the real axis
|ω|=11izzi=1|1iz|=|zi||i(z+i)|=|zi||z+i|=|zi|

Therefore, z lies on the perpendicular bisector of lin segment joining (0,1) and (0,1)
Hence, the locus of z is y=0, so z lies on the real axis.

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