CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

lf α,β,γ are the roots of the equation x3x+2=0, then the equation whose roots are αβ+1γ,βγ+1α,γα+1β, is:

A
2y3+y2+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2y3y2+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y3+y2+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2y3+y21=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B 2y3+y21=0
As α,β,γ are roots of x3x+2=0
We get s3=αβγ=2 ..(1)
Now y=αβ+1γy=αβγ+1γ
Using (1)
y=2+1γy=1xx=1y
Replacing x1y in x3x+2=0 , we get
(1y)3(1y)+2=01+y2+2y3=02y3+y21=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon