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Question


lf x2+y2=t1t and x4+y4=t2+1t2
, then x3ydydx equals

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is B 1
x2+y2=t1t
x4+y4+2x2y2=t2+1t22 ...........(1)
x4+y4=x4+y4+2x2y2+2
0=x2y2+1
1x2=y2
Differentiating both the sides w.r.t x,
1(2)x3=2ydydx
1=x3ydydx


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