CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

lf z=6eiπ3 then |eiz|=

A
1e3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1e23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1e33
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1e43
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1e33
z=6eiπ3
=6(cos(π3)+isinπ3))
=6(1+3i2)
=3(1+3i)
Hence
iz=3(3+i)
eiz=e3(3+i)
=e33.e3i
Hence
|eiz|=e33
=1e33

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Irrational Algebraic Fractions - 2
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon