CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Light of frequency $$\nu$$, wave length $$ \lambda $$ travelling with a velocity $$v$$ enters into a glass slab of refractive index $$ \mu $$ then frequency, wave length and velocity of the wave in glass slab respectively are :


A
νμ, λ, vμ
loader
B
ν, λμ, vμ
loader
C
ν, λ, vμ
loader
D
νμ, λμ, ν
loader

Solution

The correct option is B $$\nu$$, $$ \dfrac{\lambda }{\mu } $$, $$ \dfrac{v}{\mu } $$
We will use 3 concepts in this question:
1. Frequency of light does not change when light passes from one medium to another. Hence, when light enters a glass slab, it's frequency remains the same. 
$$\nu_1 = \nu_2$$
2. Refractive Index of medium 2 wrt medium 1 = (velocity of light in medium 1) / (velocity of light in medium 2)
 $$\mu = \dfrac{v_1}{v_2}$$
As we know $$\nu= v \lambda \implies v_{1} {\lambda}_1=v_2 {\lambda}_2$$ as $$\nu_1 =\nu_2$$
Hence,
$$\dfrac{v_1}{\lambda_1} = \dfrac{v_2}{\lambda_2}$$
Rearrange$$\dfrac{\lambda_1}{\lambda_2} = \dfrac{v_1}{v_2} = \mu$$

Hence, $${\lambda}_2 = \dfrac{\lambda_1}{\mu}$$
Now for velocity:
Use $$\lambda_2$$ in formula 2
$$v_2 = \dfrac{\mu}{\lambda_2}$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image