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Question

limh0(a+h)2 sin(a+h)a2 sin ah=

A
a cos a+a2 sin a
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B
a sin a+a2 cos a
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C
2a sin a+a2 cos a
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D
2a cos a+a2 sin a
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Solution

The correct option is C 2a sin a+a2 cos a
dda[a2 sin a]=2a sin a+a2 cos a
Aliter: Apply L - Hospital's rule,
limh0(a+h)2sin(a+h)a2 sin ah
=limh02(a+h)sin(a+h)+(a+h)2cos(a+h)1
=2a sin a+a2 cos a

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