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Question

limx0sin(πcos2x)x2 is equal to:
  1. π2
  2. 1
  3. π
  4. π


Solution

The correct option is D π
limx0sin(πcos2x)x2=limx0sin(ππsin2x)x2
                              =limx0sin(πsin2x)x2
                              =limx0[sin(πsin2x)πsin2xπsin2xx2]
                              =π

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