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Question

limn12+22+32n2n3 is equal to


A

1

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B

12

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C

13

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D

0

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Solution

The correct option is C

13


limn12+22+32n2n3

=limnn2n3
=limnn(n+1)(2n+1)6n3
=limn(n+1)(2n+1)6n2
Dividing the numerato5r and the denominator by n2, we get :
=limn(n+1)n×(2n+1)n6
=limn(1+1n)×(2+1n)6
26=13


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