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limπ 1ρ+2ρ+3ρ++nρnρ+1= [AIEEE 2002]


A


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B


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C


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Solution

The correct option is A



limπ 1ρ+2ρ+3ρ++nρnρ+1=limπnr=1[rρnρ+1]
=limπ1nnr=1(rn)ρ=10 xρdx=[xρ+1p+1]10=1p+1


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