limx→a(x+2)32−(a+2)32x−a
=limx→a(x+2)32−(a+2)32(x+2)−(a+2)
Let x +2 =y, a+2 =b
as x→a⇒x+2→a+2⇒y→b
⇒limy→b(y)32−(b)32(y)−(b)
[Using formula limx→axn−anx−a=nan−1]
=32(b)32−1
=32(a+2)32−1
=32(a+2)12
Find the derivative of f(x) from the first principle of where i(x) = tan x + sec x.
(ii) Evaluate limx→a (x+2)32−(a+2)32x−a