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Question

limxπ2 1-sin xπ2-x2

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Solution

limxπ21-sin xπ2-x2=limh0 1-sin π2-hπ2-π2-h2=limh0 1-cos hh2=limh0 2 sin2 h24h24 limh0 sin hh=1=12 limh0 sin h2h2212

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