CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

List- I
List- II
A. The locus of the point of intersection of the perpendicular tangents of
x2+y2=a2

1)x2+y2=5 of
B. The locus of the mid-point of the chord of the circle x2+y2=8 which is 2 units from origin is

2)x2+y2=a2sec2α
C. The locus of the point of intersection of the lines x=1t21+t2 and y=2t1+t2
3)x2+y2=2a2
D. The locus of the point whose chord of contact w.r.t x2+y2=a2
making an angle '2α' at the center is
4)x2+y2=2
5)x2+y2=1

A
3 4 5 2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3 5 4 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 4 1 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2 4 5 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3 4 5 2
(A) P is a locus of point of intersation of perperdiculer tangents.
OA=AP=r=a
OP=2 r. Using Pythegores theorem.
h2+k2=2r2=2a2
x2+y2=2a2 is a locus of P(h,k).

(B) Let P(h,k) is a middle point of chord , which is 2 units from origin
hx+ky8= h2+k28
hx+ky=h2+k2
2=h2+k2h2+k2
2=h2+k2
So locus of P(h,k)is x2+y2=2

(C) Given x=1t21+t2 and y=2t1+t2
Upon squaring and adding we get x2+y2=1

(D) Locus of p(h,k)
tan α=PAOA=h2+k2a2a
h2+k2=a2+tan2α a2
h2+k2=a2sec2α
locus of p(h,k) is x2+y2=a2sec2α

57318_33531_ans_b8e368055ec7473e9ba695c0d75b2597.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon