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Question

log xxn dx

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Solution

1xn logx dxTaking log x as the first function and 1xnas the second function.= logx1xndx-ddxlogx1xndxdx= logxx-n+1-n+1-1xx-n+1-n+1dx= logxx-n+1-n+1-x-n-n+1dx= logxx-n+1-n+1-x-n+1-n+12+C=logxx1-n1-n-x1-n1-n2+C

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