Question

# Look at the pattern and fill in the blanks:$4=3×1+1$, For ${1}^{\mathrm{st}}$ term or $n=1$ $7=3×2+1$, For ${2}^{\text{nd}}$ term or $n=2$$10=3×3+1$, For ${3}^{\mathrm{rd}}$ term or $n=3$$13=3×4+1$, For ${4}^{\mathrm{th}}$ term or $n=4$$16=3×5+1$, For ${5}^{\mathrm{th}}$ term or $n=5$$\therefore$Expression for ${n}^{\mathrm{th}}$ term is $3n+1$(iii) For $n=30$, $3×____+1=____$.

A

$30$

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B

$91$

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Solution

## The expression for ${n}^{\mathrm{th}}$ term is $3n+1$.Here, $n=30$Substituting $n=30$ in $3n+1$.We get, $3n+1$$=3\left(30\right)+1$ $=90+1$ $=91$Therefore, For $n=30$, $3×30+1=91$.

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