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Byju's Answer

Standard VIII

Physics

Units of Heat

M g of ice at...

Question

M g of ice at 0 $^{o}$ C is to be converted to water at 0 $^{o}$ C. If L is the latent heat of fusion of ice, the quantity of heat required for the above operation would be:

M L

cal

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\frac{M^{2}}{L}

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\frac{M}{L}

cal

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none of these

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Solution

The correct option is A $M L$ cal
Heat energy required = Latent heat $\times$ mass = $M L$ $c a l$

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Similar questions

Q. In a process, 10 gm of ice at

- 5^{o} C

is converted into steam at

100^{o} C

.If latent heat of fusion of ice is 80 cal

g^{- 1}

, then the amount of heat required to convert 10 g of ice at

0^{\circ} C

into 10 g of water at same temperature is :

Q. How much heat is required to change

10 g

ice at

0^{o} C

to steam at

100^{o} C

? Latent heat of fusion and vaporization for

H_{2} O

are

80 c a l / g

and

540 c a l / g

respectively. Specific heat of water is

1 c a l / g

The latent heat of fusion of solid water at $0^{\circ}$ is $80 c a l / g$ . How much heat is required to convert $4 g$ of ice at $0^{\circ}$ C to water at $0^{\circ}$ C ?

Q. The amount of heat required to convert

5 g

of ice at

0^{o} C

into water at

40^{o} C

is (Take heat of fusion

= 80 c a l / g

, specific heat

= 1 c a l / g

) :

Q. The amount of heat required to convert

1 g

of ice at

- 10^{o}

C into steam at

100^{o}

C is (specific heat of ice

= 0.5

cal/g/

^{o}

C, latent heat of ice

= 80

cal/g, latent heat of steam

= 540

cal/g)

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M g of ice at 0oC is to be converted to water at 0oC. If L is the latent heat of fusion of ice, the quantity of heat required for the above operation would be:

The correct option is A ML calHeat energy required = Latent heat × mass = ML cal

M g of ice at 0 $^{o}$ C is to be converted to water at 0 $^{o}$ C. If L is the latent heat of fusion of ice, the quantity of heat required for the above operation would be:

The correct option is A $M L$ cal
Heat energy required = Latent heat $\times$ mass = $M L$ $c a l$