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Resonance

Maam bonding ...

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Maam bonding pair electron include both bp and lp??

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Similar questions

Q. Choose the correct order of repulsions between bond pairs and lone pairs of electrons.
LP: lone pair of electrons
BP: bond pair of electrons

Q. Give the correct order of initials

T

F

for the following statements. Use

T

if statement is true and use

F

if the statement is false:
(I) The order of repulsion between pair of electrons is

l_{p} - l_{p} > l_{p} - b_{p} > b_{p} - b_{p}

l_{p} = lone pair, b_{p} = bond papir

(II) In general, as the number of lone pair of electrons on central atom increases , value of bond angle from normal bond angle also increases.
(III) The number of lone pair on

O

H_{2} O

2

N

N H_{3}

is 1.
(IV) The structures of xenon flourides and xenon oxyflourides could not be explained on the basis of VSEPR theory.

Q. Assertion :The experimentally determined

N - F

N F_{3}

is greater than the sum of the single bond covalent bond radii of

N

F

N

F

both have high electron density due to smaller atomic radii. Thus,

l p - b p

repulsion increases bond-length.

N

N H_{3}

s p^{3}

hybridised and bond angle is

107^{o}

l p - b p

repulsion (VSEPR) decreases bond angle to

107^{o}

.

Q. Hybridization is the chemist's attempt to explain the observed molecular shape by constructing hybridized atomic orbitals with the appropriate inter orbital angles. The molecule for which deviation from a normal bond angle is observed,

V S E P R

theory suggests electron pair repulsive interaction (

l p - l p > l p - b p > b p

). While from hybridization point of view that is a departure from normal hybridization because the angle between any equivalent hybrid orbitals determines the fraction of s and p characters of the hybrid and vice-versa.

In which species number of lone pairs on iodine and number of d-orbitals used in hybridization by iodine are the same?

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