CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Magnetic induction at the centre of a circular loop of area $$\pi m^2$$ is $$0.1T$$ . The magnetic moment of the loop is :
( $$\mu _{0}$$ is permeability of air)


A
0.1πμ0
loader
B
0.2πμ0
loader
C
0.3πμ0
loader
D
0.4πμ0
loader

Solution

The correct option is A $$\displaystyle \frac{0.2\pi }{\mu _{0}}$$
$$B$$ at centre of loop  = $$\dfrac { { \mu  }_{ 0 }i }{ 2r } $$
 Given area of loop is A = $$\pi$$ $$\Rightarrow r=1\ m$$
$$0.1 \ T=$$ $$\dfrac { { \mu  }_{ 0 }i }{ 2\times 1 } $$    
$$  i = $$$$\dfrac { 0.2   }{ \mu_0  } $$
Magnetic moment $$= i \times A =$$ $$\dfrac { 0.2 }{ \mu_0 } \times A\  =\  \dfrac { 0.2\pi }{ \mu_0  } $$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image