Question

Major product (A) of this reaction is:

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Oxime in presence of reagent like $H_{2}S{O}_4,P_2{O}_5,PC{l}_5,SOC{l}_2$ undergo Beckmann rearrangement to form N-Substituted amide.

Beckmann rearrangement mechanism:
Step 1: Protonation
Here, the $OH$ in oxime group is protanated and it removed as $H_{2}O$ molecule.



Step 2: Intramolecular rearrangement
Here, the group which intially present opposite to the $OH$ group will migrating to form resonating structures.



Step 3: Hydrolysis
The water molecule will attack the resonating structure and hydrolysis it and undergo tautomerism to form N-substituted amide.



In given reaction, methyl group is present opposite to $OH$ so it migrates to gives product (b).