Make b the subject of formula - a-1-b2-1-b2-

The correct option is B b=√(a 1/a+1) Given, a = 1 +b^2/1 b^2 = gt; a ab^2 = 1 +b^2 = gt; a 1 = b^2 (1 + a) = gt;b^2 = a 1/1+ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration of Irrational Algebraic Fractions - 1

Make b the su...

Question

Make b the subject of formula : $a = \frac{1 + b^{2}}{1 - b^{2}}$ .

b = \sqrt{\frac{a + 1}{a - 1}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b = \sqrt{\frac{a - 1}{a + 1}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

b = 2 \sqrt{\frac{a - 1}{a + 1}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b = 2 \sqrt{\frac{a + 1}{a - 1}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

a = \frac{1 + b^{2}}{1 - b^{2}}

b

a = 1

a = b = 1

a = b

a^{2} = a b

a^{2} - b^{2} = a b - b^{2}

(a + b) (a - b) = b (a - b)

\frac{b (a - b)}{a - b}

a + b = b

1 + 1 = 1

2 = 1

A = [\begin{matrix} 1 & - 1 \\ 2 & - 1 \end{matrix}], B = [\begin{matrix} a & 1 \\ b & - 1 \end{matrix}]

Factorize:

$a^{2} - b^{2} - 2 b - 1$

A = [\begin{matrix} 1 & - 1 2 & - 1 \end{matrix}], B = [\begin{matrix} a & 1 b & - 1 \end{matrix}]

(A + B)^{2} = A^{2} + B^{2}

a

b

Join BYJU'S Learning Program