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Question

Marks of the 100 students are distributed in the grouped frequency distribution.
Class marks
(Marks)
150 160 170 180 190 200
No. of Students 24 14 16 11 21 14

Construct the histogram for the distribution given in the table.
 


Solution

The correct option is D
As class marks or mid points are given, class intervals need to be calculated from the class marks.

Difference between the two successive classes = h = 160 - 150 =10.

If x is the class marks then,  lower and upper boundary of every class is x - h2 and  x + h2

Hence, for the first group 
lower boundary = 150 - 102 = 145
upper boundary = 150 + 102 = 155

Class interval is 145 - 155
Similarily,
Class marks Class intervals Frequency
150 145 - 155 24
160 155 - 165 14
170 165 - 175 16
180 175 - 185 11
190 185 - 195 21
200 195 - 205 14

Now make histogram with the help of above table.

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