Mass of 2 kg is moving with a string in horizontal circle with angular velocity 5 cycle/m keeping the radius constant, tension in string is doubled. Now, the angular velocity of the mass will be :

14 cycles/min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 cycles/min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.25 cycles/min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 cycles/min

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 7 cycles/min
Tension in the string should be equal to centripetal force
$T = \frac{m v^{2}}{r}$
Where m = mass of body
r = radius of circular path
v = linear velocity of body
m and r are constant
$v \propto \sqrt{T}$

$\frac{v_{1}}{v_{2}} = (\frac{T_{1}}{T_{2}})^{1 / 2} = (\frac{2 T_{2}}{T_{2}})^{1 / 2}$

$v_{2} = \sqrt{2} v_{1} = \sqrt{2} \times 5$
$= 5 \times 14 = 7$ cycles/min.

Suggest Corrections

Similar questions

Q. On applying brakes the angular velocity of a flywheel reduces from

900

cycles/min to

720

cycles/min in

6

seconds. Its angular retardation in rad

/ s^{2}

will be?

Q. On horizontal smooth surface a mass of

2 k g

is whirled in a horizontal circle by means of a string at an initial angular speed of

5 r p m

. Keeping the radius constant the tension in the string is doubled. The new angular speed is near by

Q. A sphere of mass

100 g

is rotated at uniform angular velocity of

2 r a d s^{- 1}

along a circle of radius

1.25 m

in horizontal plane with help of a light horizontal string. The tension in the string is:

A mass of 2 kg is whirled in a horizontal circle by means of a string at an initial speed of 5 revolutions per minute. Keeping the radius constant the tension in the string is doubled. The new speed is nearly

Q. A body of mass

10 k g

is rotated in vertical circle of radius

4 c m

at constant angular velocity of

5 r a d / s e c .

The maximum tension in the string is -

Mass of 2 kg is moving with a string in horizontal circle with angular velocity 5 cycle/m keeping the radius constant, tension in string is doubled. Now, the angular velocity of the mass will be :

The correct option is D 7 cycles/minTension in the string should be equal to centripetal forceT=mv2rWhere m = mass of bodyr = radius of circular pathv = linear velocity of bodym and r are constantv∝√Tv1v2=(T1T2)1/2=(2T2T2)1/2v2=√2v1=√2×5=5×14=7 cycles/min.