Question

# Mass of 92U235 required to produce electrical energy in a nuclear reactor for 30 days is 23.5kg. If 40% of the energy released by the fission is converted into electrical energy, determine the power generated by the nuclear reactor. (Assume that 200MeV energy is released per fission of 92U235 )

A
390 MW
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B
297 W
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C
297 MW
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D
27MW
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Solution

## The correct option is C 297 MWn(23592U)=23.5×103235×6.023×1023 atoms Energy released by fission =200MeV per atom Total energy released =0.1×103×6.023×1023×200×106×1.6×10−19 J=6.023×2×1.6×1014 J Electricity produced =40100×6.023×2×1.6×1014 J Power =0.4×6.023×2×1.6×101430×24×60×60=296.29×106 W

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