Match column A with their correct differentials in column B array - c - c - c - c - c - c - hlinep -cos- x -i -sin- x -v -sin - 2 x lineq -tan- x -i i -cos- x -v i -sec - 2 x lllhliner - -cosec- x - ii -sin x -cos x - vii - x -cosecx hlines- -sin - x - iii -tan x-secx- viii - x-cosecx llhlinet - - x -i v -sin x -i x -cosec- 2 x 1 linelend array A- p - ii- q - vi- r - vii- s - ii- t - viiB- p - ix- q - v- r - ix- s - iv- t - vi C- p- iv - q - vi - r - vii - s - ii - t - ix D- p - i- q - iii- r - vi- s - i- t - viii

The correct option is C p (iv); q (vi); r (vii); s (ii); t (ix) d cos x dx = sin x d tan x dx = sec^2x d sinx dx = cos x d/dx ( ...

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Standard XII

Physics

Basic Differentiation Rule

Match column ...

Question

Match column A with their correct differentials in column B

$\begin{matrix} C o l u m n A & C o l u m n B p . & c o s x & (i) & s i n x & (v) & s i n^{2} x q . & t a n x & (i i) & c o s x & (v i) & s e c^{2} x r . & c o s e c x & (i i) & s i n x c o s x & (v i i) & - c o t x c o s e c x s . & s i n x & (i i i) & t a n x s e c x & (v i i i) & c o t x c o s e c x t . & c o t x & (i v) & - s i n x & (i x) & - c o s e c^{2} x \end{matrix}$

p - (i); q - (iii); r - (vi); s - (i); t - (viii)

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p - (ii); q - (vi); r - (vii); s - (ii); t - (vii)

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p - (iv); q - (vi); r - (vii); s - (ii); t - (ix)

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p - (ix); q - (v); r - (ix); s - (iv); t - (vi)

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Solution

The correct option is C
p - (iv); q - (vi); r - (vii); s - (ii); t - (ix)

$\frac{d c o s x}{d x}$ = -sin x

$\frac{d t a n x}{d x} = s e c^{2} x$
$\frac{d s i n x}{d x}$ = cos x
$\frac{d}{d x} (c o t x) = - c o s e c^{2} x$

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Match column A with their correct differentials in column B Column A Column B p.cos x(i)sin x(v)sin2xq.tan x(ii)cos x(vi)sec2xr.cosec x(ii)sinx cosx(vii)−cotx cosecxs.sin x(iii)tanx secx(viii)cotx cosecxt.cot x(iv)−sinx(ix)−cosec2x​

The correct option is C p - (iv); q - (vi); r - (vii); s - (ii); t - (ix) d cos xdx = -sin x d tan xdx= sec2x d sinxdx = cos x ddx(cot x)=−cosec2x

The correct option is C
p - (iv); q - (vi); r - (vii); s - (ii); t - (ix)

$\frac{d c o s x}{d x}$ = -sin x

$\frac{d t a n x}{d x} = s e c^{2} x$
$\frac{d s i n x}{d x}$ = cos x
$\frac{d}{d x} (c o t x) = - c o s e c^{2} x$