CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Match each coordination compound in List - I with an appropriate pair of characteristics from List - II and select the correct answer using the code given below the lists.
{en = H2NCH2CH2NH2 'atomic numbers; Ti = 22; Cr = 24; Co = 27; Pt = 78}
List IList II(P) [Cr(NH3)4Cl2]Cl(1) Paramagnetic and exhibitsionization isomerism(Q) [Ti(H2O)5Cl](NO3)2(2) Dimagnetic and exihibitscistrans isomerism(R) [Pt(en)(NH3)Cl]NO3(3) Paramagnetic and exihibitscistrans isomerism(S) [Co(NH3)4(NO3)2]NO3(4) Diamagnetic and exihibitsinonization isomerism


Your Answer
A
P - 4, Q - 2, R - 3, S - 1
Correct Answer
B
P - 3, Q - 1, R - 4, S - 2
Your Answer
C
P - 2, Q - 1, R - 3, S - 4
Your Answer
D
P - 1, Q - 3, R - 4, S - 2

Solution

The correct option is B P - 3, Q - 1, R - 4, S - 2
List IList II(P) [Cr111(NH3)4Cl2]Cl(1) Complex given in (P) is paramagnetic(3 unpaired electrons)and shows two geometrical isomerism(cis and trans) (does not show ionization isomer)(Q) [Ti111(H2O)5Cl](NO3)2](2) Complex given in (Q) is paramagnetic(1 unpaired electrons)and shows ionization isomerism(R) [P11(en)(NH3)Cl]NO3(3) Complex given in (R) is diamagnetic(1 unpaired electrons)and shows ionization isomerism(S) [Co111(NH3)4(NO3)2]NO3(4) Complex given in (S) is diamagnetic(0 unpaired electrons)and does not show inonization isomerism(show geometrical isomerism)

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image