Question

# Match the column I with column II and mark the appropriate choice.Column IColumn II(A) XeF4(i) sp3d2(B) XeF6(ii) sp3d3(C) XeOF2(iii) sp3d(D) XeO3(iv) sp3

A
(A) (i); (B) (ii); (C) (iii); (D) (iv)
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B
(A) (iv); (B) (iii); (C) (ii); (D) (i)
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C
(A) (iii); (B) (iv); (C) (i); (D) (ii)
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D
(A) (ii); (B) (iii); (C) (iv); (D) (i)
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Solution

## The correct option is A (A) → (i); (B) → (ii); (C) → (iii); (D) → (iv)Hybridization of an atom is identified by caliculating the sum of sigma bonds and lone pairs.If sum of sigma bonds and lone pairs is 2. sp hybridizationIf sum of sigma bonds and lone pairs is 3. sp2 hybridizationIf sum of sigma bonds and lone pairs is 4. sp3 hybridization.XeO3 has 3 sigma bonds and 1 lone pair.So the sum is 4.So it is sp3 If sum of sigma bonds and lone pairs is 5. sp3d hybridization.XeOF2 has 3 sigma bonds and two lone pairs ,the sum is 5.So it is SP3d.If sum of sigma bonds and lone pairs is 6 .sp3d2 hybridization.XeF4 has 4 sigma bonds and 2 lone pair.So the sum is 6.So it is sp3d2 If sum of sigma bonds and lone pairs is 7. sp3d2 hybridization.XeF6 has 6 sigma bonds and 1 lone pair.So the sum is 7.So it is sp3d3So the option A is correct match.Hence option A is correct.

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