Question

Match the Column-I with Column-II. Choose the correct option among the following
Column – I Column – II
(A) $B{i}^{3+}⟶(BiO{)}^{+}$ (p) Heat

(B) $\left(Al{O}_2^{-}\right)⟶Al(OH{)}_3$ (q) Hydrolysis

(C) $Si{O}_4^{4-}⟶S{i}_2{O}_7^{6-}$ (r) Acidification

(D) $B_4{O}_7^{2-}⟶\left[B\right(OH{)}_3]$ (s) Dilution by water

• A. A-(q), B-(q, r), C-(p), D-(q, r)
• B. A-(r), B-(q), C-(r), D-(q)
• C. A-(q), B-(r), C-(q), D-(p)
• D. A-(q), B-(p), C-(q), D-(r)

Answer 1

The correct option is A A-(q), B-(q, r), C-(p), D-(q, r)

1. $B{i}^{3+}$ can be hydrolysed to give $[BiO{]}^{+}$. The reverse reaction can also be carried out by using 5M $HCl$.
2. Given ion is aluminate which on acidic hydrolysis readily yields a dirty white ppt of $Al(OH{)}_3$
3. Silicate on heating dimerises to give $S{i}_2{O}_7^{6-}$
4. $B_4{O}_7^{2-}$ is an ion we see in borax. We know that borax on hydrolysis gives $H_{3}B{O}_3$.