Match the Column-I with Column-II:

Column-I
(Compound) Column-II
(Oxidation state of nitrogen)

(a) $M g_{3} N_{2}$ (P) -1

(b) $N O$ (q) +2

(c) $(N_{2} H_{5})_{2} S O_{4}$ (r) -2

(d) $N H_{2} O H$ (s) -3

a-q, b-s, c-r, d-p

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a-s, b-q, c-r, d-p

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a-r, b-s, s-q, d-p

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a-p, b-s, c-q, d-r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B a-s, b-q, c-r, d-p
In $M g_{3} N_{2}$ , O.S. of $N = - \frac{6}{2} = - 3$
In NO, O.S. of $N = + 2$
In $(N_{2} H_{5})_{2} S O_{4},$
$4 x + 10 - 2 - 8 = 0 \Rightarrow x = - 2$
$∴$ OS of $N = - 2$
In $N H_{2} O H,$ OS of $N = - 1$

Suggest Corrections

Similar questions

Match Column I with Column II with reference to types of reaction:

$\begin{matrix} Column I & Column II A. & Ionization reaction & p. & {CH}_{4} + 2 O_{2} \to {CO}_{2} + 2 H_{2} O B. & Dissociation reaction & q. & H_{2} O_{2} \to H_{2} O + O_{2} C. & Decomposition reaction & r. & Mg {Cl}_{2} \to {Mg}^{2 +} + 2 {Cl}^{-} D. & Combustion reaction & s. & {H_{2} O}_{(basic)} + {H_{2} O}_{(acidic)} \to H_{3} O^{+} + {OH}^{-} \end{matrix}$

Match the type of fibre in column-I with their uses and characterstics in column-II
$\begin{matrix} Column - I & Column - II A. Acrylic & P. Contains repeating ester units B. Cellulose & Q. Used for making sweaters C. Polythene & R. Made up of large number of glucose units D. Terylene & S. Used for manufacturing toys. \end{matrix}$

Q. Answer the following by appropriately matching the lists based on the information in Column I and Column II

\begin{matrix} C o l u m n I & C o l u m n I I a . y = f (x) is given by x = t^{5} - 5 t^{3} - 20 t + 7 and y = 4 t^{3} - 3 t^{2} - 18 t + 3. Then - 5 \times \frac{d y}{d x} at t = 1 & p. 0 b . Let P (x) be a polynomial of degree 4, with P (2) = - 1, P^{'} (2) = 0, P^{''} (2) = 2, P^{'''} (2) = - 12 and P^{i v} (2) = 24, then P^{''} (3) is & q. - 2 c . y = \frac{1}{x}, then \frac{\frac{d y}{\sqrt{1 + y^{4}}}}{\frac{d x}{\sqrt{1 + x^{4}}}} & r . 2 d . f (\frac{2 x + 3 y}{5}) = \frac{2 f (x) + 3 f (y)}{5} and f^{'} (0) = p and f (0) = q . Then, f^{''} (0) is & s. - 1 \end{matrix}

Q. Match the following (for a satellite in circular orbit)

\begin{matrix} C o l u m n - I & C o l u m n - I I (a) & Kinetic energy & (p) & - \frac{G M m}{2 r} (b) & Potential energy & (q) & \sqrt{\frac{G M}{r}} (c) & Total energy & (r) & - \frac{G M m}{r} (d) & Orbital velocity & (s) & \frac{G M m}{2 r} \end{matrix}

Q. Match the Column-I with Column-II. Choose the correct option among the following
Column – I Column – II
(A) Borax (p)

s p^{3}

hybridization of B
(B)

B F_{3}

(q)

s p^{2}

hybridization of B
(C) Diborane (r) Triangular unit
(D) Boric acid (s) Tetrahedral unit

Join BYJU'S Learning Program

Column-I (Compound)	Column-II (Oxidation state of nitrogen)
(a) $M g_{3} N_{2}$	(P) -1
(b) $N O$	(q) +2
(c) $(N_{2} H_{5})_{2} S O_{4}$	(r) -2
(d) $N H_{2} O H$	(s) -3

Match the Column-I with Column-II: Column-I (Compound) Column-II (Oxidation state of nitrogen) (a) Mg3N2 (P) -1 (b) NO (q) +2 (c) (N2H5)2SO4 (r) -2 (d) NH2OH (s) -3

The correct option is B a-s, b-q, c-r, d-pIn Mg3N2, O.S. of N=−62=−3 In NO, O.S. of N=+2 In (N2H5)2SO4, 4x + 10 −2 −8 =0⇒x=−2 ∴OS of N=−2 In NH2OH, OS of N=−1

Match the Column-I with Column-II:

Column-I
(Compound) Column-II
(Oxidation state of nitrogen)

(a) $M g_{3} N_{2}$ (P) -1

(b) $N O$ (q) +2

(c) $(N_{2} H_{5})_{2} S O_{4}$ (r) -2

(d) $N H_{2} O H$ (s) -3

The correct option is B a-s, b-q, c-r, d-p
In $M g_{3} N_{2}$ , O.S. of $N = - \frac{6}{2} = - 3$
In NO, O.S. of $N = + 2$
In $(N_{2} H_{5})_{2} S O_{4},$
$4 x + 10 - 2 - 8 = 0 \Rightarrow x = - 2$
$∴$ OS of $N = - 2$
In $N H_{2} O H,$ OS of $N = - 1$